The Rarest Seed in Minecraft! (Rarer Than Fully Completed End Portal)
This Minecraft seed is one of the rarest ever found — rarer than spawning with a fully lit End Portal!
In this world, a Woodland Mansion, a Stronghold, and a massive Ancient City all generate directly on top of each other.
It’s a once-in-a-lifetime world generation — with a probability of around 1 in 18 billion worlds.
In this video, I’ll explain exactly how Minecraft’s structure generation works — from the rings of strongholds around spawn, to how Woodland Mansions only appear in Dark Forests roughly once every 6,400 chunks, and how Ancient Cities form deep underground beneath specific terrain noise patterns.
This seed somehow breaks every statistical expectation and aligns perfectly with all three.
If you enjoy rare Minecraft seeds, world generation anomalies, and insane luck moments, you’ll love this one.
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🌍 Seed: 27989392284679975
🎮 Version: Minecraft Java Edition 1.19.2
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🌍 Seed: 27989392284679975
🎮 Version: Minecraft Java Edition 1.19.2
📍 Coordinates: 232, -1704
Here's all the probability calculations:
1) Chance a single stronghold’s End Portal is fully lit (all 12 Eyes)
Each portal frame block independently has probability 1/10 = 0.1 to spawn with an Eye.
Probability all 12 frames are filled in one portal = (1/10)¹² = 10^(-12).
Numeric: (1/10)¹² = 1.000000000000 × 10^(-12).
1 in 1,000,000,000,000 (one in one trillion) for a single stronghold.
2) Chance a world has at least one fully lit End Portal (128 strongholds)
There are 128 strongholds per Java world. For tiny p, world chance ≈ 128 × p.
Use p = 10^(-12) from (1): world probability ≈ 128 × 10^(-12) = 1.28 × 10^(-10).
Convert to “1 in X”: 1 / (1.28 × 10^(-10)) = 7,812,500,000 ≈ 1 in 7.8 billion.
So: world-level chance ≈ 1.28e-10 ≈ 1 in 7.8 billion for at least one fully lit portal.
3) How we model a Woodland Mansion appearing at a given X/Z (mansion + stronghold math)
Mansion placement attempt density (spacing): 1 attempt per 80×80 chunks = 1 / 80² = 1 / 6,400 = 0.00015625 attempts per chunk.
Not every attempt succeeds: it only succeeds if the chunk passes the Dark Forest / pale-garden biome/terrain checks. Call that fraction fM (fraction of chunks that are valid mansion-placement chunks).
Per-chunk probability a mansion actually exists at a given chunk column: p_M = (1 / 6400) × fM = 0.00015625 × fM.
Treat 128 stronghold X/Z columns as 128 independent trials. World probability (approx) that at least one stronghold column has a mansion at the same X/Z ≈ 128 × p_M (valid because p_M is tiny).
Simplify the constant: 128 × 0.00015625 = 0.02 exactly. So P_world(mansion+stronghold) ≈ 0.02 × fM.
Numeric examples (pick fM):
If fM = 0.0002 (0.02% of chunks eligible): p_M = 0.00015625 × 0.0002 = 3.125 × 10⁻⁸ → P_world ≈ 128 × 3.125e-8 = 4.000e-6 → ≈ 1 in 250,000.
If fM = 0.0008 (0.08% — the “mid” used earlier): p_M = 1.25 × 10⁻⁷ → P_world ≈ 1.60 × 10⁻⁵ → ≈ 1 in 62,500.
If fM = 0.002 (0.2% — generous): p_M = 3.125 × 10⁻⁷ → P_world ≈ 4.00 × 10⁻⁵ → ≈ 1 in 25,000.
Summary: mansion+stronghold per world ≈ 0.02 × fM, examples give ~1 in 25k → 1 in 250k depending on fM.
4) Exact formula and numeric example for the three-structure stack (Mansion above Stronghold above Ancient City)
Ancient City attempt density (spacing): 1 attempt per 24×24 chunks = 1 / 24² = 1 / 576 = 0.0017361111111111111 attempts per chunk.
Let fA = fraction of chunks that pass the Ancient City deep-dark/noise filter (i.e., chunk-level success fraction for Ancient City). Per-chunk Ancient City probability: p_A = (1 / 576) × fA = 0.0017361111111111111 × fA.
For a given stronghold column, approximate probability both a mansion and an ancient city exist at that same X/Z (independence approximation) = p_M × p_A.
Per-world probability across 128 strongholds ≈ 128 × p_M × p_A. Substitute p_M and p_A:
P_stack ≈ 128 × (1/6400 × fM) × (1/576 × fA)
= [128 / (6400 × 576)] × (fM × fA).
Compute the constant precisely: 6400 × 576 = 3,686,400. 128 / 3,686,400 = 0.00003472222222222222 = 3.4722222222222222 × 10⁻⁵.
Final compact formula: P_stack ≈ 3.4722222222222222 × 10⁻⁵ × (fM × fA).
Numeric example (the mid estimate used earlier): fM = 0.0008 (0.08%), fA = 0.002 (0.2%).
fM × fA = 0.0008 × 0.002 = 1.6 × 10⁻⁶.
Multiply by constant: P_stack ≈ 3.4722222222222222e-5 × 1.6e-6 = (3.4722222222222222 × 1.6) × 10^(-11) = 5.555555555555556 × 10⁻¹¹.
Odds: 1 / 5.555555555555556e-11 ≈ 18,000,000,000 → ≈ 1 in 18 billion worlds.
Range examples to show sensitivity:
Low case: fM = 0.0002, fA = 0.0005 → fM×fA = 1.0e-10 → P_stack ≈ 3.4722222e-15 → ~1 in 2.88e14 (extremely tiny).
High case: fM = 0.002, fA = 0.005 → fM×fA = 1.0e-5 → P_stack ≈ 3.4722222e-10 → ~1 in 2.88e9 (~1 in 2.9 billion).
Summary: three-structure stack P_stack ≈ 3.4722222e-5 × (fM × fA). With mid-range fM/fA the estimate is ≈ 5.56e-11 → ~1 in 18 billion; changing fM/fA moves this by orders of magnitude.
Bro recharged his CAS and calculated his password to be (log(10)69,420)
bro what
Bro I think 18 billion is smaller than 1 trillion 😂
so 18b is bigger than 1t now??
1 time I found a golden apple with efficiency 1 on a random seed
I love how he goes from and that is why to the very beginning so smoothly. It's an infinite glitch😮
Like your skin
Yeah bro, I don’t think you’re know how numbers work
I'm I feel.like a pee lit end portal is a bit more rare
Pls stop hiting the air
You do realize that 1 trillion is rarer then 18 billion right?
Definition of ethical behavior: doing the right thing even when no one is watching and even if the wrong thing is legal
She was not very ethical